I want to parse the 'url' attribute in enclosure tag
I have seen only samples using DefaultHandler.any way to do it using AndroidSaxFeedParser
Enclosure tag is inside the tag Item
Code: public List parse() throws IOException, SAXException { final Message currentMessage = new Message(); RootElement root = new RootElement(RSS); final List messages = new ArrayList(); Element channel = root.getChild(CHANNEL);
channel.getChild(LASTBUILDATE).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
lastBuildDate = body;
}
});
Element item = channel.getChild(ITEM);
item.setEndElementListener(new EndElementListener(){
public void end() {
currentMessage.setLastBuildDate(lastBuildDate);
messages.add(currentMessage.copy());
}
});
item.getChild(TITLE).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setTitle(body);
}
});
item.getChild(LINK).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setLink(body);
}
});
item.getChild(DESCRIPTION).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setDescription(body);
}
});
item.getChild(PUB_DATE).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setDate(body);
}
});
item.getChild(CATEGORY).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setCategory(body);
}
});
item.getChild(GUID).setEndTextElementListener(new EndTextElementListener(){
public void end(String body) {
currentMessage.setGuid(body);
}
});
Xml.parse(this.getInputStream(), Xml.Encoding.UTF_8, root.getContentHandler());
return messages;
}
.
stackoverflow.comm
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