[android help] logical operation in java

logical operation in java

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	I have been trying to implement the following condition in a more sofisticated manner: if (x > 1) doSomething(); else { doSomething(); } want to code it like: (x > 1) ? doSomething() : doSomething(); Is this not possible at all? asked 5 mins ago

Not possible if doSomething() returns void. Refer the JLS 15.25 The first expression must be of type boolean or Boolean, or a compile-time error occurs. It is a compile-time error for either the second or the third operand expression to be an invocation of a void method. In fact, by the grammar of expression statements (§14.8), it is not permitted for a conditional expression to appear in any context where an invocation of a void method could appear. P.S: Why you want to doSomething() for both true or false? answered 4 mins ago

	Not in full generality; the arguments in the ternary (formally the ternary requires expressions) have to evaluate to the same type. If doSomething() is a void type then certainly not. answered 4 mins ago

	It is dependent on return type.If you define like this void doSomething() then its not possible. answered 1 min ago

	No you can't. In JLS §14.8 ExpressionStatement: StatementExpression ; StatementExpression: Assignment PreIncrementExpression PreDecrementExpression PostIncrementExpression PostDecrementExpression MethodInvocation ClassInstanceCreationExpression Oops, no ConditionalExpression at all. answered 1 min ago

	The ternary is used for inline if conditions. They need a return value, because u could write something like that: System.out.println((x > 1) ? "True" : "False"); with void this would not be possible answered 10 secs ago

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